hlswuwu 发表于 2025-4-7 10:44:49

AES加解密怎么返回十六进制啊

.版本 2

.子程序 _按钮1_被单击
.局部变量 b, 文本型

b ＝ 编码_AES加密 (“0X01,0XAB,0X02,0X00,0X55,0X05,0X00,0X07,0X08,0X09,0X0A,0X0B,0X0C,0X0D,0X0E,0X0F”, “0X00,0X01,0X02,0X03,0X04,0X05,0X06,0X07,0X08,0X09,0X0A,0X0B,0X0C,0X0D,0X0E,0X0F”, , #Mode_ECB, , 2, 2, 真, 真)
调试输出文本 (b)



怎么返回十六进制文本呢

hlswuwu 发表于 2025-4-7 10:54:15

密钥：0X00,0X01,0X02,0X03,0X04,0X05,0X06,0X07,0X08,0X09,0X0A,0X0B,0X0C,0X0D,0X0E,0X0F
明文：0X01,0XAB,0X02,0X00,0X55,0X05,0X00,0X07,0X08,0X09,0X0A,0X0B,0X0C,0X0D,0X0E,0X0F
密文：0xa8,0Xde,0X42,0X19,0Xbe,0X83,0X09,0Xda,0X46,0Xe0,0X15,0Xdf,0X5a,0X2a,0X96,0X1e

hlswuwu 发表于 2025-4-7 10:54:32

像这样的怎么解出来啊

揰掵佲 发表于 2025-4-7 19:33:26

应该是16进制转字节集
字节集转16进制

hlswuwu 发表于 2025-4-8 08:58:10

嗯会了啊啊啊
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